HHL on a 2×2 system

The matrix $A$ has eigenvalues $\lambda_1=\tfrac23$ and $\lambda_2=\tfrac43$. Phase estimation with $U=e^{iAt}$, $t=\tfrac{3\pi}{4}$ and $t_c=2$ clock qubits writes the integer $k_j=\lambda_j t\,2^{t_c}/(2\pi)$ into the clock register. Enter the two clock values $k_1,k_2$ (in either order). Exact integers are expected (tolerance $10^{-9}$).

The circuit is fixed: ancilla on qubit $0$, clock on qubits $1$ (MSB) and $2$ (LSB), system on qubit $3$ starting in $\lvert b\rangle=\lvert0\rangle$. It runs phase estimation (controlled-$U$ from qubit $2$, controlled-$U^2=-X$ from qubit $1$, inverse QFT), the rotations $\mathrm{CRY}(2\to0,\theta_1)$ and $\mathrm{CRY}(1\to0,\theta_2)$, and the exact inverse of phase estimation. Set the parameters $\texttt{theta1}$ and $\texttt{theta2}$ so that, conditioned on ancilla $=1$ and clock $=00$, the system qubit is $\lvert x\rangle=A^{-1}\vec b/\lVert A^{-1}\vec b\rVert=(3,1)/\sqrt{10}$. The grader requires fidelity $\ge0.9999$ and success probability $\ge0.6$. Use $C=1$: the rotation for clock value $k$ must map $\lvert0\rangle\mapsto\sqrt{1-C^2/k^2}\,\lvert0\rangle+(C/k)\lvert1\rangle$.