Hands-on lab · 1 step
Build the product state |+⟩ ⊗ |1⟩
Use single-qubit gates only to prepare on two qubits, and see why the Kronecker order (qubit is the left factor) decides which qubit gets which gate.
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Step 1: Prepare |+⟩ ⊗ |1⟩
Starting from , prepare
Convention: qubit is the most significant bit, i.e. the left tensor factor, so basis state has index and a gate on qubit with on qubit acts as .
Allowed gates: (single-qubit only, at most gates, no two-qubit gates). The grader requires fidelity .