Compile the ZZ evolution from CNOT and RZ

Build a two-qubit circuit whose unitary equals

$T=e^{-i\frac{\theta}{2}Z\otimes Z}\Big|_{\theta=0.7}=\begin{pmatrix}e^{-0.35i}&0&0&0\\0&e^{0.35i}&0&0\\0&0&e^{0.35i}&0\\0&0&0&e^{-0.35i}\end{pmatrix}.$

Qubit $0$ is the most significant bit, so the basis order is $\lvert00\rangle,\lvert01\rangle,\lvert10\rangle,\lvert11\rangle$, and the diagonal entry of $\lvert ab\rangle$ is $e^{-0.35i\,(-1)^{a\oplus b}}$ because $Z\otimes Z\lvert ab\rangle=(-1)^{a\oplus b}\lvert ab\rangle$.

The gate conventions are $R_Z(\theta)=e^{-i\theta Z/2}=\mathrm{diag}(e^{-i\theta/2},e^{i\theta/2})$ and $\mathrm{CNOT}\lvert a,b\rangle=\lvert a,a\oplus b\rangle$ (first listed qubit = control). Only CNOT and $R_Z$ are allowed, at most three gates in total. The grader computes your circuit unitary $U$ and the process fidelity $F_U=\lvert\mathrm{Tr}(T^\dagger U)\rvert/4$, which equals $1$ exactly when $U=e^{i\gamma}T$ for some real $\gamma$, and requires $F_U\ge1-10^{-6}$.